Integrand size = 20, antiderivative size = 308 \[ \int \frac {(c x)^{5/2}}{\left (a-b x^2\right )^{3/4}} \, dx=-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}-\frac {3 a c^{5/2} \arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}\right )}{4 \sqrt {2} b^{7/4}}+\frac {3 a c^{5/2} \arctan \left (1+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}\right )}{4 \sqrt {2} b^{7/4}}+\frac {3 a c^{5/2} \log \left (\sqrt {c}+\frac {\sqrt {b} \sqrt {c} x}{\sqrt {a-b x^2}}-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt [4]{a-b x^2}}\right )}{8 \sqrt {2} b^{7/4}}-\frac {3 a c^{5/2} \log \left (\sqrt {c}+\frac {\sqrt {b} \sqrt {c} x}{\sqrt {a-b x^2}}+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt [4]{a-b x^2}}\right )}{8 \sqrt {2} b^{7/4}} \]
-1/2*c*(c*x)^(3/2)*(-b*x^2+a)^(1/4)/b+3/8*a*c^(5/2)*arctan(-1+b^(1/4)*2^(1 /2)*(c*x)^(1/2)/(-b*x^2+a)^(1/4)/c^(1/2))/b^(7/4)*2^(1/2)+3/8*a*c^(5/2)*ar ctan(1+b^(1/4)*2^(1/2)*(c*x)^(1/2)/(-b*x^2+a)^(1/4)/c^(1/2))/b^(7/4)*2^(1/ 2)+3/16*a*c^(5/2)*ln(c^(1/2)-b^(1/4)*2^(1/2)*(c*x)^(1/2)/(-b*x^2+a)^(1/4)+ x*b^(1/2)*c^(1/2)/(-b*x^2+a)^(1/2))/b^(7/4)*2^(1/2)-3/16*a*c^(5/2)*ln(c^(1 /2)+b^(1/4)*2^(1/2)*(c*x)^(1/2)/(-b*x^2+a)^(1/4)+x*b^(1/2)*c^(1/2)/(-b*x^2 +a)^(1/2))/b^(7/4)*2^(1/2)
Time = 0.57 (sec) , antiderivative size = 164, normalized size of antiderivative = 0.53 \[ \int \frac {(c x)^{5/2}}{\left (a-b x^2\right )^{3/4}} \, dx=-\frac {(c x)^{5/2} \left (4 b^{3/4} x^{3/2} \sqrt [4]{a-b x^2}+3 \sqrt {2} a \arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {x} \sqrt [4]{a-b x^2}}{\sqrt {b} x-\sqrt {a-b x^2}}\right )+3 \sqrt {2} a \text {arctanh}\left (\frac {\sqrt {b} x+\sqrt {a-b x^2}}{\sqrt {2} \sqrt [4]{b} \sqrt {x} \sqrt [4]{a-b x^2}}\right )\right )}{8 b^{7/4} x^{5/2}} \]
-1/8*((c*x)^(5/2)*(4*b^(3/4)*x^(3/2)*(a - b*x^2)^(1/4) + 3*Sqrt[2]*a*ArcTa n[(Sqrt[2]*b^(1/4)*Sqrt[x]*(a - b*x^2)^(1/4))/(Sqrt[b]*x - Sqrt[a - b*x^2] )] + 3*Sqrt[2]*a*ArcTanh[(Sqrt[b]*x + Sqrt[a - b*x^2])/(Sqrt[2]*b^(1/4)*Sq rt[x]*(a - b*x^2)^(1/4))]))/(b^(7/4)*x^(5/2))
Time = 0.49 (sec) , antiderivative size = 301, normalized size of antiderivative = 0.98, number of steps used = 13, number of rules used = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.600, Rules used = {262, 266, 854, 27, 826, 1476, 1082, 217, 1479, 25, 27, 1103}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \frac {(c x)^{5/2}}{\left (a-b x^2\right )^{3/4}} \, dx\) |
\(\Big \downarrow \) 262 |
\(\displaystyle \frac {3 a c^2 \int \frac {\sqrt {c x}}{\left (a-b x^2\right )^{3/4}}dx}{4 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 266 |
\(\displaystyle \frac {3 a c \int \frac {c x}{\left (a-b x^2\right )^{3/4}}d\sqrt {c x}}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 854 |
\(\displaystyle \frac {3 a c \int \frac {c^3 x}{b x^2 c^2+c^2}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {3 a c^3 \int \frac {c x}{b x^2 c^2+c^2}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 826 |
\(\displaystyle \frac {3 a c^3 \left (\frac {\int \frac {\sqrt {b} x c+c}{b x^2 c^2+c^2}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {b}}-\frac {\int \frac {c-\sqrt {b} c x}{b x^2 c^2+c^2}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {b}}\right )}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 1476 |
\(\displaystyle \frac {3 a c^3 \left (\frac {\frac {\int \frac {1}{x c+\frac {c}{\sqrt {b}}-\frac {\sqrt {2} \sqrt {c x} \sqrt {c}}{\sqrt [4]{b} \sqrt [4]{a-b x^2}}}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {b}}+\frac {\int \frac {1}{x c+\frac {c}{\sqrt {b}}+\frac {\sqrt {2} \sqrt {c x} \sqrt {c}}{\sqrt [4]{b} \sqrt [4]{a-b x^2}}}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {b}}}{2 \sqrt {b}}-\frac {\int \frac {c-\sqrt {b} c x}{b x^2 c^2+c^2}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {b}}\right )}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 1082 |
\(\displaystyle \frac {3 a c^3 \left (\frac {\frac {\int \frac {1}{-c x-1}d\left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}-\frac {\int \frac {1}{-c x-1}d\left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}-\frac {\int \frac {c-\sqrt {b} c x}{b x^2 c^2+c^2}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {b}}\right )}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 217 |
\(\displaystyle \frac {3 a c^3 \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}-\frac {\int \frac {c-\sqrt {b} c x}{b x^2 c^2+c^2}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {b}}\right )}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 1479 |
\(\displaystyle \frac {3 a c^3 \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}-\frac {-\frac {\int -\frac {\sqrt {2} \sqrt {c}-\frac {2 \sqrt [4]{b} \sqrt {c x}}{\sqrt [4]{a-b x^2}}}{\sqrt [4]{b} \left (x c+\frac {c}{\sqrt {b}}-\frac {\sqrt {2} \sqrt {c x} \sqrt {c}}{\sqrt [4]{b} \sqrt [4]{a-b x^2}}\right )}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {2} \sqrt [4]{b} \sqrt {c}}-\frac {\int -\frac {\sqrt {2} \left (\sqrt {c}+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt [4]{a-b x^2}}\right )}{\sqrt [4]{b} \left (x c+\frac {c}{\sqrt {b}}+\frac {\sqrt {2} \sqrt {c x} \sqrt {c}}{\sqrt [4]{b} \sqrt [4]{a-b x^2}}\right )}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}\right )}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {3 a c^3 \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}-\frac {\frac {\int \frac {\sqrt {2} \sqrt {c}-\frac {2 \sqrt [4]{b} \sqrt {c x}}{\sqrt [4]{a-b x^2}}}{\sqrt [4]{b} \left (x c+\frac {c}{\sqrt {b}}-\frac {\sqrt {2} \sqrt {c x} \sqrt {c}}{\sqrt [4]{b} \sqrt [4]{a-b x^2}}\right )}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {2} \sqrt [4]{b} \sqrt {c}}+\frac {\int \frac {\sqrt {2} \left (\sqrt {c}+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt [4]{a-b x^2}}\right )}{\sqrt [4]{b} \left (x c+\frac {c}{\sqrt {b}}+\frac {\sqrt {2} \sqrt {c x} \sqrt {c}}{\sqrt [4]{b} \sqrt [4]{a-b x^2}}\right )}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}\right )}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {3 a c^3 \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}-\frac {\frac {\int \frac {\sqrt {2} \sqrt {c}-\frac {2 \sqrt [4]{b} \sqrt {c x}}{\sqrt [4]{a-b x^2}}}{x c+\frac {c}{\sqrt {b}}-\frac {\sqrt {2} \sqrt {c x} \sqrt {c}}{\sqrt [4]{b} \sqrt [4]{a-b x^2}}}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {2} \sqrt {b} \sqrt {c}}+\frac {\int \frac {\sqrt {c}+\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt [4]{a-b x^2}}}{x c+\frac {c}{\sqrt {b}}+\frac {\sqrt {2} \sqrt {c x} \sqrt {c}}{\sqrt [4]{b} \sqrt [4]{a-b x^2}}}d\frac {\sqrt {c x}}{\sqrt [4]{a-b x^2}}}{2 \sqrt {b} \sqrt {c}}}{2 \sqrt {b}}\right )}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
\(\Big \downarrow \) 1103 |
\(\displaystyle \frac {3 a c^3 \left (\frac {\frac {\arctan \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}+1\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}-\frac {\arctan \left (1-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c x}}{\sqrt {c} \sqrt [4]{a-b x^2}}\right )}{\sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}-\frac {\frac {\log \left (\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c} \sqrt {c x}}{\sqrt [4]{a-b x^2}}+\sqrt {b} c x+c\right )}{2 \sqrt {2} \sqrt [4]{b} \sqrt {c}}-\frac {\log \left (-\frac {\sqrt {2} \sqrt [4]{b} \sqrt {c} \sqrt {c x}}{\sqrt [4]{a-b x^2}}+\sqrt {b} c x+c\right )}{2 \sqrt {2} \sqrt [4]{b} \sqrt {c}}}{2 \sqrt {b}}\right )}{2 b}-\frac {c (c x)^{3/2} \sqrt [4]{a-b x^2}}{2 b}\) |
-1/2*(c*(c*x)^(3/2)*(a - b*x^2)^(1/4))/b + (3*a*c^3*((-(ArcTan[1 - (Sqrt[2 ]*b^(1/4)*Sqrt[c*x])/(Sqrt[c]*(a - b*x^2)^(1/4))]/(Sqrt[2]*b^(1/4)*Sqrt[c] )) + ArcTan[1 + (Sqrt[2]*b^(1/4)*Sqrt[c*x])/(Sqrt[c]*(a - b*x^2)^(1/4))]/( Sqrt[2]*b^(1/4)*Sqrt[c]))/(2*Sqrt[b]) - (-1/2*Log[c + Sqrt[b]*c*x - (Sqrt[ 2]*b^(1/4)*Sqrt[c]*Sqrt[c*x])/(a - b*x^2)^(1/4)]/(Sqrt[2]*b^(1/4)*Sqrt[c]) + Log[c + Sqrt[b]*c*x + (Sqrt[2]*b^(1/4)*Sqrt[c]*Sqrt[c*x])/(a - b*x^2)^( 1/4)]/(2*Sqrt[2]*b^(1/4)*Sqrt[c]))/(2*Sqrt[b])))/(2*b)
3.10.80.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^( -1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])], x] /; FreeQ[{a, b}, x] && PosQ[a/b] & & (LtQ[a, 0] || LtQ[b, 0])
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> Simp[c*(c*x) ^(m - 1)*((a + b*x^2)^(p + 1)/(b*(m + 2*p + 1))), x] - Simp[a*c^2*((m - 1)/ (b*(m + 2*p + 1))) Int[(c*x)^(m - 2)*(a + b*x^2)^p, x], x] /; FreeQ[{a, b , c, p}, x] && GtQ[m, 2 - 1] && NeQ[m + 2*p + 1, 0] && IntBinomialQ[a, b, c , 2, m, p, x]
Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^2)^(p_), x_Symbol] :> With[{k = De nominator[m]}, Simp[k/c Subst[Int[x^(k*(m + 1) - 1)*(a + b*(x^(2*k)/c^2)) ^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && FractionQ[m] && I ntBinomialQ[a, b, c, 2, m, p, x]
Int[(x_)^2/((a_) + (b_.)*(x_)^4), x_Symbol] :> With[{r = Numerator[Rt[a/b, 2]], s = Denominator[Rt[a/b, 2]]}, Simp[1/(2*s) Int[(r + s*x^2)/(a + b*x^ 4), x], x] - Simp[1/(2*s) Int[(r - s*x^2)/(a + b*x^4), x], x]] /; FreeQ[{ a, b}, x] && (GtQ[a/b, 0] || (PosQ[a/b] && AtomQ[SplitProduct[SumBaseQ, a]] && AtomQ[SplitProduct[SumBaseQ, b]]))
Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[a^(p + (m + 1)/n) Subst[Int[x^m/(1 - b*x^n)^(p + (m + 1)/n + 1), x], x, x/(a + b*x^n )^(1/n)], x] /; FreeQ[{a, b}, x] && IGtQ[n, 0] && LtQ[-1, p, 0] && NeQ[p, - 2^(-1)] && IntegersQ[m, p + (m + 1)/n]
Int[((a_) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> With[{q = 1 - 4*S implify[a*(c/b^2)]}, Simp[-2/b Subst[Int[1/(q - x^2), x], x, 1 + 2*c*(x/b )], x] /; RationalQ[q] && (EqQ[q^2, 1] || !RationalQ[b^2 - 4*a*c])] /; Fre eQ[{a, b, c}, x]
Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> S imp[d*(Log[RemoveContent[a + b*x + c*x^2, x]]/b), x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ 2*(d/e), 2]}, Simp[e/(2*c) Int[1/Simp[d/e + q*x + x^2, x], x], x] + Simp[ e/(2*c) Int[1/Simp[d/e - q*x + x^2, x], x], x]] /; FreeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && PosQ[d*e]
Int[((d_) + (e_.)*(x_)^2)/((a_) + (c_.)*(x_)^4), x_Symbol] :> With[{q = Rt[ -2*(d/e), 2]}, Simp[e/(2*c*q) Int[(q - 2*x)/Simp[d/e + q*x - x^2, x], x], x] + Simp[e/(2*c*q) Int[(q + 2*x)/Simp[d/e - q*x - x^2, x], x], x]] /; F reeQ[{a, c, d, e}, x] && EqQ[c*d^2 - a*e^2, 0] && NegQ[d*e]
\[\int \frac {\left (c x \right )^{\frac {5}{2}}}{\left (-b \,x^{2}+a \right )^{\frac {3}{4}}}d x\]
Timed out. \[ \int \frac {(c x)^{5/2}}{\left (a-b x^2\right )^{3/4}} \, dx=\text {Timed out} \]
Result contains complex when optimal does not.
Time = 3.83 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.15 \[ \int \frac {(c x)^{5/2}}{\left (a-b x^2\right )^{3/4}} \, dx=\frac {c^{\frac {5}{2}} x^{\frac {7}{2}} \Gamma \left (\frac {7}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{4}, \frac {7}{4} \\ \frac {11}{4} \end {matrix}\middle | {\frac {b x^{2} e^{2 i \pi }}{a}} \right )}}{2 a^{\frac {3}{4}} \Gamma \left (\frac {11}{4}\right )} \]
c**(5/2)*x**(7/2)*gamma(7/4)*hyper((3/4, 7/4), (11/4,), b*x**2*exp_polar(2 *I*pi)/a)/(2*a**(3/4)*gamma(11/4))
\[ \int \frac {(c x)^{5/2}}{\left (a-b x^2\right )^{3/4}} \, dx=\int { \frac {\left (c x\right )^{\frac {5}{2}}}{{\left (-b x^{2} + a\right )}^{\frac {3}{4}}} \,d x } \]
\[ \int \frac {(c x)^{5/2}}{\left (a-b x^2\right )^{3/4}} \, dx=\int { \frac {\left (c x\right )^{\frac {5}{2}}}{{\left (-b x^{2} + a\right )}^{\frac {3}{4}}} \,d x } \]
Timed out. \[ \int \frac {(c x)^{5/2}}{\left (a-b x^2\right )^{3/4}} \, dx=\int \frac {{\left (c\,x\right )}^{5/2}}{{\left (a-b\,x^2\right )}^{3/4}} \,d x \]